Question

a rectangular piece of aluminum foil (density = 2.700 g/cm*3) is 25.70 cm wide and 28.32 cm long. it has a mass of 7.291 g. what is the thickness of the foil (height) in cm? put answer in correct sig fig.

Answer 1

let's calculate the volume of the aluminum foil using the density

$density= \frac{mass}{volume} -----\ \textgreater \ volume= \frac{mass}{density}$

$volume= \frac{7.291 grams}{2.700 g/cm^3} =$ $2.700 cm^3$

let's recall the volume of a rectangle formula

$Rectangle_{volume}=$ height x wide x long

we already have long and wide, and volume. so let's solve for the unknown

$2.700 cm^3= heightx 25.70 cm x 28.32 cm$

$height= \frac{2.700}{25.70 x 29.32} = 0.003710 cm$