Question

What is the concentration of an Ammonia (NH3) solution when 25.0 g of Ammonia are dissolved in enough water to produce 650.0 mL of solution?

Answer 1

to find the concentration, use the following formula--> molarity= moles/ liters

liters= 650.0 mL= 0.6500 Liters

we need to convert the grams to moles using the molar mass of NH3

molar mass of NH3 = 14.0  + (3 x 1.01)= 17.03 g/ mol

25.0 g NH3 ( 1 mol/ 17.03 grams)= 1.47 mol

concentration= 1.47 mol/ 0.6500 Liters= 2.26 M