Question

Can someone plssssssssss help me with this maths question.
. .
Prove that the recurring decimal 0.15 has the value 5/33

Answer 1

x = 0,(15) | * 100
100x = 15,(15) | - 0,(15)
99x = 15 | ÷ 99
x = 15/99 = 5/33

Answer 2

$x=0.\overline{15}\\100x=15.\overline{15}\\\\100x-x=15.\overline{15}-0.\overline{15}\\99x=15\\x=\dfrac{15}{99}=\dfrac{5}{33}$