A 43.63 gram sample of a hydrate of caseo4 was heated thoroughly in a porcelain crucible, until its weight remained constant. after heating, 36.45 grams of the anhydrous compound remained. what is the formula of the hydrate?
let the hydrated compound be CaSO4.xH2O mass of the caso4= 43.63g /(40+32+64+18x)* (40+32+64)= 36.45g 136+18x=( 43.63*136) / 36.45= 162.78 18x = 162.78- 136= 26.8 x = 1.48 = 1.5 Formula of hydrate = CaSO4.1.5H2O = 2CaSo4. 3H2O
