Question

Hello, can you please express this without denominators with the work?

$\frac{a^4b}{c^2d^3}$

Thanks a lot!

Answer 1

$\bf a^{-{ n}} \implies \cfrac{1}{a^{ n}}\qquad \qquad \cfrac{1}{a^{ n}}\implies a^{-{ n}} \\ \quad \\ % negative exponential denominator a^{{ n}} \implies \cfrac{1}{a^{- n}} \qquad \qquad \cfrac{1}{a^{- n}}\implies \cfrac{1}{\frac{1}{a^{ n}}}\implies a^{{ n}} \\\\ -----------------------------\\\\ \cfrac{a^4b}{c^2d^3}\implies \cfrac{a^4}{1}\cdot \cfrac{b^1}{1}\cdot \cfrac{1}{c^2}\cdot \cfrac{1}{d^3}\implies a^4\cdot b^1\cdot c^{-2}\cdot d^{-3}\implies a^4bc^{-2}d^{-3}$