Question

evaluate 3 plus the square root of x + 19 minus the square root of 2 x when x equals 6

Answer 1

=3+*sqr root*6 +19 - *sqr root* 12
=21 + *sqr root* 6 - *sqr root* 12
= 21+ *sqr root* 6 - 2 square roots of 6