Question

In the following combustion reaction of acetylene (C2H2), how many liters of CO2 will be produced if 60 liters of O2 is used, given that both gases are at STP?
2C2H2+5O2 2H2O+4CO2

The volume of one mole of gas at STP is 22.4 liters.

Answer 1

2C₂H₂ + 5O₂ = 2H₂O + 4CO₂

V(O₂)=60 l
Vm=22.4 l/mol (the numeric value does not need)

V(O₂)/{5Vm}=V(CO₂)/{4Vm}

V(CO₂)=4V(O₂)/5

V(CO₂)=4*60/5=48 l

48  liters of CO₂ will be produced