A drawer holds 8 red socks, 13 blue socks, and 15 green socks. what is the probability that a red sock will be drawn first and then a green sock (without replacement?

This is the concept of probability, given that there are 8 red socks, 13 blues socks and 15 green socks, we are required to find that the first socks chosen will a red then a green; Here we shall proceed as follows;
The events are dependent
P(choosing a red socks )=8/36=2/9
P(choosing green socks after red)=15/35=3/7
Thus the probability of choosing red socks then a green socks without replacement will be:
2/9*3/7
=2/21

Answer Link

MrRoyal MrRoyal · Answer 2 · 2022-06-01T15:19:45+02:00

The probability that a red sock will be drawn first and then a green sock (without replacement) is 0.0952

How to determine the probability?

The distribution of the socks is given as:

8 red socks, 13 blue socks, and 15 green socks

The total number of socks is:

Total = 8 + 13 + 15

Total = 36

The probability of selecting a red socks is:

P(Red) = 8/36

Now, there are 35 socks

The probability of selecting a green socks is:

P(Green) = 15/35

The required probablity is:

P = 8/36 * 15/35

Evaluate

P = 0.0952

Hence, the probability that a red sock will be drawn first and then a green sock (without replacement) is 0.0952