Respuesta :

To find the center and radius given your equation, remember (x-h)^2 + (y-k)^2 = r^2, where (h,k) is the center of the circle and r is the radius. In your equation, h = 3 and k = 6 and since 2^2 =4 your r value is 2. So the center is at (3,6) and the radius is 2.
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Answer:

To find the center and radius given your equation, remember (x-h)^2 + (y-k)^2 = r^2, where (h,k) is the center of the circle and r is the radius. In your equation, h = 3 and k = 6 and since 2^2 =4 your r value is 2. So the center is at (3,6) and the radius is 2.