Respuesta :
Probability to get a success is 0 AND one
1) P(getting 0) = 1/8 ( from 0 to 7 = 8 numbers)
2) P(getting 1) = 1/8
P(1 and 0) = 1/8 x 1/8 = 1/64 =0.0156 = 1.56%
1) P(getting 0) = 1/8 ( from 0 to 7 = 8 numbers)
2) P(getting 1) = 1/8
P(1 and 0) = 1/8 x 1/8 = 1/64 =0.0156 = 1.56%
Answer:
Hence, the estimated probability of a success=0.0156 or 1.56%.
Step-by-step explanation:
Let P denotes the probability of an event
we are given number from 0 to 7.
Total number of outcomes=8
Now 0 an 1 represent a success.
Probability of getting 0 i.e. P(0)=[tex]\dfrac{1}{8}[/tex]
similarly,
Probability of getting 1 i.e. P(1)=[tex]\dfrac{1}{8}[/tex]
Hence, the estimate probability of success:
i.e.
[tex]P(1 and 0)=\dfrac{1}{8}\times \dfrac{1}{8}=\dfrac{1}{64}=0.0156=1.56%[/tex].
(since the events are independent)