Question

excluded values for y=5/(6x-72)
(the / is a fraction so its 5 over 6x)

Answer 1

The denominator cannot equal zero. Set the expression on the denominator = to zero to find the value that must be excluded.
6x - 72 = 0
add 72 to both sides
6x = 72
Divide both sides by 6
x = 9
The excluded value is 9.