Respuesta :
Answer:
(A)[tex]70cm^2[/tex]
Step-by-step explanation:
Given is the trapezoid which consists of two triangles and one rectangle, thus from ΔPST, we have
[tex]\frac{PT}{ST}=tan45^{\circ}[/tex]
⇒[tex]\frac{5}{ST}=1[/tex]
⇒[tex]ST=5cm[/tex]
Now, area ΔPST=[tex]\frac{1}{2}{\times}5{\times}5=\frac{25}{2}cm^2[/tex]
Also, area ΔQUR=[tex]\frac{1}{2}{\times}5{\times}3=\frac{15}{2}cm^2[/tex]
Area rectangle PQUT=[tex]l{\times}b=10{\times}5=50cm^2[/tex]
Therefore, area trapezoid PQRS= area ΔPST+area ΔQUR+Area rectangle PQUT
=[tex]\frac{25}{2}+\frac{15}{2}+50[/tex]
=[tex]70cm^2[/tex]
Hence, area of trapezoid= [tex]70cm^2[/tex]