Question

Slaked lime (Ca(OH)2) is formed from quicklime (CaO) by the addition of water. What mass of slaked lime can be produced from a mixture of 22.4g of CAO and 10.9g of H2O CaO(s)+H2O(l)=Ca(OH)2(s)

Answer 1

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Answer 2

The mass of slaked lime will be 29.6 g.

What is mass?

The mass of a thing is the quantity of matter as well as a substance that makes it up. It is expressed in kilograms, which may be abbreviated as kg. It's crucial to keep in mind that mass is not the same as weight. Although mass remains constant, weight fluctuates due to variations in gravity.

Calculation of mass of slaked lime is shown as:

The given chemical equation is CaO(s)+H2O(l) → Ca(OH)2(s)

No of moles of H2O = 10.9 g/ 18 g = 0.606 mol.

No of moles of CaO = 22.4 g / 56 g = 0.4 mol.

Here, CaO will be limiting reagent.

Mass of slaked lime can be calculated as:

Mass  =  0.4 mol × (40 +16 × 2 + 2)

Mass = 29.6 g.

Therefore, the mass of slaked lime will be 29.6 g.

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