Question

How many moles of hcl are present in 0.70 l of a 0.33 m hcl solution? (molar mass of hcl = 36.46 g/mol?

Answer 1

v=0.7 l
c=0.33 moles/l

n(HCl)=v·c

n(HCl) = 0.7 l · 0.33 moles/l = 0.231 moles

0.231 moles of HCl are present