Respuesta :
if i am not mistake u can use -log[concentration of oh-] to find it
ie -log[6.4*10^-10]=9.19
ie -log[6.4*10^-10]=9.19
Answer: Yes. The pH = 7.6 .
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Explanation:
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pH = - log [H⁺] ; in which, by convention, we assume that there
is an implied "base 10" if there is no number listed as a
"base" under the "log" sign;
i.e. , " pH = - log [H⁺]⁺ = - log₍₁₀₎ [H⁺] ;
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in which, the: " [H⁺] " refers to the concentration of hydrogen ions, or " H⁺ " ; in "Molarity" ; that is: "moles of solutes per Liters of solution", or "mol / L", or "M" .
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Likewise, "pOH = - log [OH⁻] = - log₍₁₀₎ [OH⁻] " .
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Note: pH + pOH = 14 .
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So, given: "A solution with 6.4 * 10⁻¹⁰ M OH (in our problem), find the "pH".
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The pOH of the solution is 6.4 .
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Since pH + pOH = 14 ;
we can substitute "6.4" for "pOH" ; and solve for "pH":
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pH + 6.4 = 14 ;
Subtract "6.4" from each side of the equation; to isolate "pH" on one side of the equation; and to solve for the "pH" ;
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pH + 6.4 − 6.4 = 14 − 6.4 ;
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pH = 7.6 .
_________________________________________________
___________________________________________________
Explanation:
____________________________________________________
pH = - log [H⁺] ; in which, by convention, we assume that there
is an implied "base 10" if there is no number listed as a
"base" under the "log" sign;
i.e. , " pH = - log [H⁺]⁺ = - log₍₁₀₎ [H⁺] ;
________________________________________________
in which, the: " [H⁺] " refers to the concentration of hydrogen ions, or " H⁺ " ; in "Molarity" ; that is: "moles of solutes per Liters of solution", or "mol / L", or "M" .
________________________________________________
Likewise, "pOH = - log [OH⁻] = - log₍₁₀₎ [OH⁻] " .
________________________________________________
Note: pH + pOH = 14 .
________________________________________________
So, given: "A solution with 6.4 * 10⁻¹⁰ M OH (in our problem), find the "pH".
_________________________________________________
The pOH of the solution is 6.4 .
_________________________________________________
Since pH + pOH = 14 ;
we can substitute "6.4" for "pOH" ; and solve for "pH":
_________________________________________________
pH + 6.4 = 14 ;
Subtract "6.4" from each side of the equation; to isolate "pH" on one side of the equation; and to solve for the "pH" ;
_________________________________________________
pH + 6.4 − 6.4 = 14 − 6.4 ;
_________________________________________________
pH = 7.6 .
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