well, we know each car holds 5 folks, we know also that the "interior" angles of the wheel sum up to 7740º, so hmm how many cars on that "regular polygon" wheel anyway?
well [tex]\bf \textit{sum of all interior angles in a polygon}\\\\
s=180(n-2)\
\begin{cases}
n=\textit{sides in the polygon}\\
----------\\
s=7740
\end{cases}\implies 7740=180(n-2)
\\\\\\
\cfrac{7740}{180}=n-2\implies 43=n-2\implies \boxed{45=n}[/tex]
so the ferris wheel has 45 sides, is a polygon of 45 sides... that means it has 45 cars, each car can hold 5 folks, so it can hold a maximum of 45 *5
