Trigonometric functions are the ratio of different sides of a right-angled triangle. The distance between the points Y and Y' is 9.2 units.
What are Trigonometric functions?
The trigonometric function gives the ratio of different sides of a right-angle triangle.
[tex]\rm Sin \theta=\dfrac{Perpendicular}{Hypotenuse}\\\\\\Cos \theta=\dfrac{Base}{Hypotenuse}\\\\\\Tan \theta=\dfrac{Perpendicular}{Base}[/tex]
where perpendicular is the side of the triangle which is opposite to the angle, and the hypotenuse is the longest side of the triangle which is opposite to the 90° angle.
Given to us
XY = XY' = 5 units
YZ = Y'Z = 12 units
XZ = 13 units
In ΔXYZ,
We know that in a right-angled triangle, we can apply trigonometric function, therefore, for ∠YXZ
[tex]\rm Tan(\theta) = \dfrac{Perpendicular}{Base}\\\\Tan(\angle YXZ) = \dfrac{YZ}{XY}\\\\Tan(\angle YXZ) = \dfrac{12}{5}\\\\Tan(\angle YXZ) = 2.4\\\\\angle YXZ = Tan^{-1}\ 2.4\\\\\angle YXZ = 67.38^o[/tex]
In ΔXYE,
[tex]\rm Sin(\theta) = \dfrac{Perpendicular}{Hypotenuse}\\\\Sin(\angle XYE) = \dfrac{YE}{XY}\\\\SIn(67.38^o) = \dfrac{YE}{5}\\\\YE = 4.6154[/tex]
Thus, the length of the line YE is 4.6154 units.
Now, we know that the ΔXY'Z is the reflection of the ΔXYZ, therefore, the length of the line YE=Y'E. The distance between the point Y and Y' can be written as,
YY' = YE+EY'
YY' = 4.6154 + 4.6154
YY' = 9.23
YY' = 9.2 units
Hence, the distance between the point Y and Y' is 9.2 units.
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