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Triangle XYZ is reflected over its hypotenuse to create a kite.

What is the approximate distance from Y to Y’? Round to the nearest tenth.

A. 4.6 units
B. 5.4 units
C. 8.0 units
D. 9.2 units (dumb answers will be reported)

Triangle XYZ is reflected over its hypotenuse to create a kite What is the approximate distance from Y to Y Round to the nearest tenth A 46 units B 54 units C 8 class=

Respuesta :

The angle between line XZ and line XY is given by:

[tex] x = atan (\frac{12}{5})

x = 67.38
[/tex]

Then, the height from vertex Y to horizontal line XZ is:

[tex] h = 5 sine (67.38)

h = 4.62
[/tex]

Then, the distance from Y to Y 'is given by:

[tex] YY '= 2h

YY '= 2 (4.62)

YY '= 9.2
[/tex]

Answer:

the approximate distance from Y to Y 'is:

D. 9.2 units

Trigonometric functions are the ratio of different sides of a right-angled triangle. The distance between the points Y and Y' is 9.2 units.

What are Trigonometric functions?

The trigonometric function gives the ratio of different sides of a right-angle triangle.

[tex]\rm Sin \theta=\dfrac{Perpendicular}{Hypotenuse}\\\\\\Cos \theta=\dfrac{Base}{Hypotenuse}\\\\\\Tan \theta=\dfrac{Perpendicular}{Base}[/tex]

where perpendicular is the side of the triangle which is opposite to the angle, and the hypotenuse is the longest side of the triangle which is opposite to the 90° angle.

Given to us

XY = XY' = 5 units

YZ = Y'Z = 12 units

XZ = 13 units

In ΔXYZ,

We know that in a right-angled triangle, we can apply trigonometric function, therefore, for ∠YXZ

[tex]\rm Tan(\theta) = \dfrac{Perpendicular}{Base}\\\\Tan(\angle YXZ) = \dfrac{YZ}{XY}\\\\Tan(\angle YXZ) = \dfrac{12}{5}\\\\Tan(\angle YXZ) = 2.4\\\\\angle YXZ = Tan^{-1}\ 2.4\\\\\angle YXZ = 67.38^o[/tex]

In ΔXYE,

[tex]\rm Sin(\theta) = \dfrac{Perpendicular}{Hypotenuse}\\\\Sin(\angle XYE) = \dfrac{YE}{XY}\\\\SIn(67.38^o) = \dfrac{YE}{5}\\\\YE = 4.6154[/tex]

Thus, the length of the line YE is 4.6154 units.

Now, we know that the ΔXY'Z is the reflection of the ΔXYZ, therefore, the length of the line YE=Y'E. The distance between the point Y and Y' can be written as,

YY' = YE+EY'

YY' = 4.6154 + 4.6154

YY' = 9.23

YY' = 9.2 units

Hence, the distance between the point Y and Y' is 9.2 units.

Learn more about Trigonometric functions:

https://brainly.com/question/6904750

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