Respuesta :
[tex]\bf \qquad \textit{parabola vertex form}\\\\
\begin{array}{llll}
\boxed{y=a(x-{{ h}})^2+{{ k}}}\\\\
x=a(y-{{ k}})^2+{{ h}}
\end{array} \qquad\qquad vertex\ ({{ h}},{{ k}})\\\\
-----------------------------\\\\
\textit{vertex at -5,-2}\quad
\begin{cases}
h=-5\\
k=-2\\
\end{cases}\implies y=a(x-(-5))^2+(-2)
\\\\\\
y=a(x+5)^2-2\quad
\begin{cases}
x=-4\\
y=2
\end{cases}\implies \underline{2}=a(\underline{-4}+5)^2-2
\\\\\\
2=a(1)^2-2\implies \boxed{4=a}[/tex]
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