Question

How much heat does 225 g of water gain when its temperature rises from 25°C to 32°C?

Answer 1

Q = (m) (Csh) (T2 - T1) 
Q = (225 g) (4.184 J/g -C) (32.0C - 25.0C)
Q = 6590
J = 6.59 kJ

Answer 2

Answer:

1575 Cal

Explanation:

Between this temperature range, the water does not change state since its boiling point is at 100 degrees Celsius.

As there is no change of state we use the sensible heat formula

 The specific heat of liquid water is $1\frac{Cal}{g.C}$

We substitute in the formula

$Q=225g.1\frac{Cal}{g.C} .(32-25)C\\ Q=1575 Cal$