Question

A jar contains only dimes and quarters. The number of quarters is 8 less than the number of dimes. The value of the coins is $4.30.

A) Write an equation that you can use to solve for the number of dimes, d.

B) How many dimes are in the jar?










PLEASE HELP IM CLUELESS

Answer 1

Write out equations for each condition...

The number of quarters is 8 less than the number of dimes:

q=d-8

The value of the coins is $4.30.

Each quarter is worth 25 cents and each dime is worth 10 cents, and the total value of all of the coins is 4.3*100=430 cents so we can say:

25q+10d=430, and if we use q=d-8 from earlier in this equation we have:

25(d-8)+10d=430  perform indicated multiplication on left side

25d-200+10d=430  combine like terms on left side

35d-200=430  add 200 to both sides

35d=630 divide both sides by 35

d=18

So there are 18 dimes in the jar.

Answer 2

There are 18 dimes and 10 quarters. 18x.10= $1.80 and 10x.25=$2.50 . $2.50+$1.80= $4.30