Question

Find Each Sum.
(–4c2 + 7cd + 8d) + (–3d + 8c2 + 4cd) =

Answer 1

To add monomials, you have to look at the variables that are accompanied by their coefficients. In the given problem, (–4c2 + 7cd + 8d) + (–3d + 8c2 + 4cd), you can combine both cd ut nt cd and c² and cd and d and d and c² because they have different variables.

(–4c2 + 7cd + 8d) + (–3d + 8c2 + 4cd) 
(-4c² + 8c²) + (7cd + 4cd) + (8d - 3d)
4c² + 11cd + 5d

Answer 2

The resulting sum of the values (–4c2 + 7cd + 8d) + (–3d + 8c2 + 4cd) is 4c² + 11cd + 5d

Taking the the sum of the values :

• (-4c² + 7cd + 8d) + (-3d + 8c² + 4cd)

Open the bracket :

• -4c² + 7cd + 8d - 3d + 8c² + 4cd

Collect like terms :

• -4c² + 8c² + 7cd + 4cd + 8d - 3d

The sum :

• 4c² + 11cd + 5d

Therefore, the sum of the values is 4c² + 11cd + 5d

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