Respuesta :
2 sin t cos t + √3 cos t = 0
cos t ( 2 sin t + √3 ) = 0
Therefore:
cos t = 0, t 1 = π/2, t 2 = 3 π/2
or:
2 sin t + √3 = 0
2 sin t = - √3
sin t = - √3 / 2
t 3 = 4 π/3, t 4 = 5 π/3
Answer:
a ) π/2, 4π/3, 3π/2. 5π/3.
cos t ( 2 sin t + √3 ) = 0
Therefore:
cos t = 0, t 1 = π/2, t 2 = 3 π/2
or:
2 sin t + √3 = 0
2 sin t = - √3
sin t = - √3 / 2
t 3 = 4 π/3, t 4 = 5 π/3
Answer:
a ) π/2, 4π/3, 3π/2. 5π/3.
HI!!! I just finished the unit 7 lesson 11 unit test!! Here are the answers: :)
1. A: 2
2. C: 225
3. C: pi/4
4. A: -465
5. C: 0
6. B: 210
7. B: 2pi
8. A: 52
9. C: 40
10. C: 3rd graph
11. A: y=sin pi/265
12. B: 1/4pi
13. D: y=3cos2
14. A: sqrt3/3
15. C: 0
16. C: 3rd graph
17. A: 187
18. C: sqrt2/2
19. B: 1+sin theta
20. D: 45
21. D: 0.64
22. A:80
23. C: pi/2, 5pi/4, 3pi/2, 7pi/4
24. C: csc theta =13/12, sec theta= 13/5
hope this helps someone :)))