Respuesta :

The power supplied to the motor by the fuel cell is 0.31 watts.

The current , I is 0.5 A.
Voltage, V is 0.43 V

From ohm's law: V = IR 
Thus, R = 0.43/0.5 = 0.86Ω

Now, Power = [tex] I^{2} [/tex]R
                     = 0.5 ×0.5×0.86
                     = 0.215 W
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