Respuesta :
Hi there
Use the formula of the present value of annuity ordinary and solve for pmt
Pmt=pv÷[(1-(1+r)^(-n))÷r]
PMT=150,261÷((1−(1+0.091)^(−20))÷(0.091))=16,578.03
Hope it helps
Use the formula of the present value of annuity ordinary and solve for pmt
Pmt=pv÷[(1-(1+r)^(-n))÷r]
PMT=150,261÷((1−(1+0.091)^(−20))÷(0.091))=16,578.03
Hope it helps
Answer:
$16,574.24
Step-by-step explanation:
We know the annuity formula is given by,
[tex]P=\frac{r \times PV}{1-(1+r)^{-n} }[/tex]
where P = annual payment, PV = present value, r = rate of interest and n = time period.
We have according to the question,
PV = $150,261
r = 9.1% = 0.091
n = 20
Substituting the values in the formula gives us,
[tex]P=\frac{0.091 \times 150261}{1-(1+0.091)^{-20}}[/tex]
i.e. [tex]P=\frac{13673.751}{1-(1.091)^{-20}}[/tex]
i.e. [tex]P=\frac{13673.751}{1-0.175}[/tex]
i.e. [tex]P=\frac{13673.751}{0.825}[/tex]
i.e. [tex]P=16,574.2437[/tex]
So, the annual withdrawals is of $16,574.2437
After rounding off to nearest cent ( or hundred ), the annual withdrawals is $16,574.24.