Respuesta :
In Terms of y:
y = -(2)/(5x) + 40
y = (-2) + (5x)40
y = 200x - 2/5x
In Terms of x:
y = -(2)/(5x) + 40
y = (-2) + (5x)40/5x
y = -2 + 5x • 40/5x
x = - 2/5y - 200
y = -(2)/(5x) + 40
y = (-2) + (5x)40
y = 200x - 2/5x
In Terms of x:
y = -(2)/(5x) + 40
y = (-2) + (5x)40/5x
y = -2 + 5x • 40/5x
x = - 2/5y - 200
Answer:
Excluded values of the given function is -8.
Step-by-step explanation:
Given Function is [tex]y=\frac{-2}{5x+40}[/tex]
We have to find Excluded values of the function.
We know that Values excluded from function are the values where functions cease to exist.
We are given a function with numerator and denominator.
So, When denominator becomes zero the function cease to exist.
⇒ Value of x when denominator become 0 are excluded from function.
Denominator from given function is 5x + 40
Put,
5x + 40 = 0
5x = 0 - 40
5x = -40
[tex]x=\frac{-40}{5}[/tex]
x = -8
Therefore, Excluded values of the given function is -8.