Respuesta :

Zane18
In Terms of y:
y = -(2)/(5x) + 40
y = (-2) + (5x)40
y = 200x - 2/5x
In Terms of x:
y = -(2)/(5x) + 40
y = (-2) + (5x)40/5x
y = -2 + 5x • 40/5x
x = - 2/5y - 200

Answer:

Excluded values of the given function is -8.

Step-by-step explanation:

Given Function is [tex]y=\frac{-2}{5x+40}[/tex]

We have to find Excluded values of the function.

We know that Values excluded from function are the values where functions cease to exist.

We are given a function with numerator and denominator.

So, When denominator becomes zero the function cease to exist.

Value of x when denominator become 0 are excluded from function.

Denominator from given function is 5x + 40

Put,

5x + 40 = 0

5x = 0 - 40

5x = -40

[tex]x=\frac{-40}{5}[/tex]

x = -8

Therefore, Excluded values of the given function is -8.

ACCESS MORE
EDU ACCESS