Question

a gas is confined in a steel tank with a volume og 6.982L at 20.20c the gas exerts a pressure of 8.532 atm.after heating the tank the pressure of gas increases to 10.406atm.what is the temperature of the heated gas convert celsius temp to kelvins

Answer 1

To solve this we assume that the gas is an ideal gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At a constant volume and number of moles of the gas the ratio of T and P is equal to some constant. At another set of condition, the constant is still the same. Calculations are as follows:

T1/P1 = T2/P2

T2 = T1 x P2 / P1

T2 = (20.20+273.15) x 10.406 / 8.532

T2 = 357.782 K or 84.632 C

Answer 2

Answer:

84.59°C

Explanation:

Using Gay-Lussac’s law

P1/T1 = P2/T2