Question

Jamie just bought 2 boxes. The first box is square.With each side measuring 10units and is 4 units high.The second box is rectangular and has twice the volume of the square box. if the height of the second box is 5units and the width is 10 units what is the length of the second box

Answer 1

You are given two boxes. The first box is a square with each side measuring 10units and 4 units high. The second box is a rectangle with a height of 5 units and width of 10 units. If the second box has twice the volume of the second box, then you need to find the volume of the square.

square
V = bh
V = 10(10)(4) 
V = 400

Rectangle
V = LWH
2(400) = 10(5)H
H = 16 units

Answer 2

From the volume we know that the value of the height of the rectangle will be equal to 16 units.

Given the information that:

• Square: Side 10units and is 4 units height
• Rectangular: twice the volume of the square box and width is 10 units

So calculating the volume of the square, we have:

$V = bh\\V = 10(10)(4) \\V = 400$

With the volume of the square we will calculated the height as:

$V = LWH\\2(400) = 10(5)H\\H = 16 units$

See more about volume at brainly.com/question/1578538