Question

The volume of a gas is 250ml at 340.0 kPa pressure. What will the volume be when the pressure is reduced to 50.0 kPa, assuming the temperature remains constant?

Answer 1

The volume will be 1700 ml when the pressure is reduced to 50.0 kPa, assuming the temperature remains constant.

Boyle's Law

Boyle's law is a gas law which states that at constant temperature (T), the pressure (P) of a given quantity of a gas varies inversely with its volume (V) occupied by it.  

According to the Boyle's Law:

PV = constant

Thus,

$P_{1}V_{1} = P_{2} V_{2}$

where,

$P_{1}$ is the initial pressure

$V_{1}$ is the initial volume

$P_{2}$ is the final pressure

$V_{2}$ is the final volume

Here,

$P_{1}$ = 340.0 kPa, $P_{2}$ = 50.0 kPa,

$V_{1}$ = 250 ml and $V_{2}$ = ?

Now, put the values in above equation we get

$P_{1} V_{1} = P_{2} V_{2}$

340 kPa × 250 ml = 50.0 kPa × $V_{2}$

$V_{2} = \frac{340 kPa \times 250ml}{50.0 kPa}$

$V_{2} = \frac{85000}{50}$

$V_{2}$ = 1700 ml

Thus, the volume will be 1700 ml when the pressure is reduced to 50.0 kPa, assuming the temperature remains constant.

Learn more about Boyle's Law here: https://brainly.com/question/1696010

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