Question

If 0.45 mols of MnO2 can react with 0.28 moles of HCl, how many moles of Cl2 could be produced

Answer 1

MnO₂ + 4HCl = MnCl₂ + 2H₂O + Cl₂

n(MnO₂)=0.45 mols
n(HCl)=0.28 mols

0.45 : 0.28 = 1 : 0.622
the reaction equation   1:4
the hydrogen chloride in the lack

n(Cl₂)=n(HCl)/4
n(Cl₂)=0.28/4=0.07 mols
formed 0.07 mols of chlorine