Δ ABC is an isosceles right triangle:∠ ABC =∠BCA = V45°
Δ ACE is also a right triangle (inscribed in half a circle. The sum of its angles = 180° and ∠CAE + ∠ACE = 90 ; ∠ CAE + 57° *given) = 90°, then ∠ CAE = 33° CALCULATE ∠ BAE: ∠ BAE = ∠BAC + ∠CAE ∠BAE = 45° + 33° = 78°
