Respuesta :
[tex]\bf \cfrac{14ab^3}{7a^{-2}b^{-1}}\\\\
-----------------------------\\\\
a^{-{ n}} \implies \cfrac{1}{a^{ n}}\qquad \qquad
\cfrac{1}{a^{ n}}\implies a^{-{ n}}
\\ \quad \\
% negative exponential denominator
a^{{ n}} \implies \cfrac{1}{a^{- n}}
\qquad \qquad
\cfrac{1}{a^{- n}}\implies \cfrac{1}{\frac{1}{a^{ n}}}\implies a^{{ n}} \\\\
-----------------------------\\\\
[/tex]
[tex]\bf \cfrac{14}{7}\cdot \cfrac{a}{1}\cdot \cfrac{1}{a^{-2}}\cdot \cfrac{b^3}{1}\cdot \cfrac{1}{b^{-1}}\implies 2\cdot a\cdot a^2\cdot b^3\cdot b^1\implies 2a^{1+2}b^{3+1} \\\\\\ 2a^3b^4[/tex]
[tex]\bf \cfrac{14}{7}\cdot \cfrac{a}{1}\cdot \cfrac{1}{a^{-2}}\cdot \cfrac{b^3}{1}\cdot \cfrac{1}{b^{-1}}\implies 2\cdot a\cdot a^2\cdot b^3\cdot b^1\implies 2a^{1+2}b^{3+1} \\\\\\ 2a^3b^4[/tex]
Answer:
2a2 – 2b – 1
Step-by-step explanation:
this was right on edge