Answer:
The molecular formula is N3O6
Explanation:
The empirical formula of the compound is NO2
Now, find the number of empirical units in each mole of compound a. The empirical mass of the compound is found by adding one mole of nitrogen (14.0067 g/mol), and two moles of OXYGEN (16.00 g/mole). Compare this to given molar mass to determine the whole-number multiplier.
(1*14.0067 g) +(2*16.00 g) = 46.0067 g/ emp.unit
a = 138.02 g/mole/ 46.0067 g/ emp.unit
= 2.99≈3
The molecular formula is NO2 *3= N3O6