Question

You and a friend each roll a standard die to see who goes first in a board game. What is the probability that at least one of you rolls a 6? lookin for a friend

Answer 1

What say you have two dices
You have 36 possibilities
11 / 36
30.56 %

Answer 2

Answer: $=\frac{11}{36}$

Step-by-step explanation:

According to the question,

Event = at least one of friend has 6

Favorable outcomes would look like (1,6), (2,6), (3,6), (4,6), (5,6), (6,6), (6,1),(6,2),(6,3),(6,4),(6,5)

Thus the number of favorable outcomes=11

Similarly, total number of outcomes= 36

Probability of that at least one of friend rolls a 6 $=\frac{\text{favorable outcomes}}{\text{total outcomes}}$

$=\frac{11}{36}$