Question

An aluminum can with a mass of 12.8 g absorbs 212 J of heat. By how much does the temperature of the can increase? The specific heat capacity of aluminum is 0.91j/g * k

Answer 1

Heat gained or absorbed in a system can be calculated by multiplying the given mass to the specific heat capacity of the substance and the temperature difference. It is expressed as follows:

Heat = mC(T2-T1)

We calculate as follows:

212 J = 12.8 (0.91)(ΔT)

ΔT = 18.20 K

The increase in temperature is about 18.20 Kelvin.