Question

You roll a number cube twice find P even then not too I'm right there probability as a fraction in simplest form

Answer 1

1. So the question is P(first even then not 2)

2. P(first even then not 2)= $\frac{n(first even then not 2)}{n(sample space)}$

3. n(first even then not 2)=n{(2,1),(2,3),(2,4),(2,5),(2,6),(4,1),(4,3),(4,4),(4,5),(4,6),(6,1),(6,3),(6,4),(6,5),(6,6)}=15

4. n(sample space)= 6(possible outcomes for the first throw)*6(for the second throw)=36

5. P(first even then not 2)=$\frac{15}{36}$