Question

Which ionic equation represents a spontaneous reaction that can occur in a voltaic cell? 1. Cu(s) + Zn(s) → Cu2+(aq) + Zn2+(aq) 2. Cu(s) + Zn2+(aq) → Cu2+(aq) + Zn(s) 3. Cu2+(aq) + Zn(s) → Cu(s) + Zn2+(aq) 4. Cu2+(aq) + Zn2+(aq) → Cu(s) + Zn(s)

Answer 1

Answer : The correct option is, (3) $Cu^{2+}(aq)+Zn(s)\rightarrow Cu(s)+Zn^{2+}(aq)$

Explanation :

Voltaic cell : It is defined as a device which is used for the conversion of the chemical energy produces in a redox reaction into the electrical energy. It is also known as the galvanic cell or electrochemical cell.

The redox reaction occurs between the zinc and copper sulfate.

In the voltaic cell, the oxidation occurs at an anode which is a negative electrode and the reduction occurs at the cathode which is a positive electrode.

The balanced two-half reactions will be,

Oxidation half reaction : $Zn(s)\rightarrow Zn^{2+}(aq)+2e^-$

Reduction half reaction : $Cu^{2+}(aq)+2e^-\rightarrow Cu(s)$

Thus the overall reaction will be,

$Zn(s)+Cu^{2+}(aq)\rightarrow Zn^{2+}(aq)+Cu(s)$

Answer 2

The spontaneous reaction equation is the reaction; Cu2+(aq) + Zn(s) → Cu(s) + Zn2+(aq).

What is a spontaneous ionic reaction?

A spontaneous ionic reaction will have a positive cell potential. In this case, we have to look at the relative positions of the metals in the electrochemical series.

Hence, the spontaneous reaction equation is the reaction; Cu2+(aq) + Zn(s) → Cu(s) + Zn2+(aq).

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