In the pendulum formula , we use g = 9.8 m/s2 for the acceleration due to gravity on Earth. But what about on Mars? If an astronaut on the surface of Mars swings a 1-meter long pendulum, and it has a period of 3.27 seconds, what is the acceleration due to gravity, g, on Mars?

Respuesta :

Answer:

Acceleration would be 3.7 m/s² due to gravity on Mars.

Step-by-step explanation:

We use the pendulum formula :

T = [tex]2\pi \sqrt{\frac{L}{g} }[/tex]

Where L = 1 n

T = 3.27 seconds

∴ 3.27 = [tex]2\pi \sqrt{\frac{1}{g} }[/tex]

= [tex]\frac{3.27}{2\pi } =\sqrt{\frac{1}{g} }[/tex]

= 0.5207 = [tex]\sqrt{\frac{1}{g} }[/tex]

= 0.2711 = [tex]\frac{1}{g}[/tex]

= g = [tex]\frac{1}{0.2711}[/tex]

g = 3.68 m/s² or 3.7 m/s²

Acceleration would be 3.7 m/s² due to gravity on Mars.

Answer:

3.7 m/s²

Step-by-step explanation:

A p e x

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