Question

A solution has a volume of 2.0 L and contains 36.0 grams of glucose (C6H12O6). If the molar mass of glucose is 180 g/mol, what is the molarity of the solution?

Answer 1

36.0 g of glucose divided by 180 g/mol = 0.200 moles of glucose 

find molarity
0.200 moles of glucose / 2 liters = 0.100 molar solution 

(hope this helps)