Question

Methane (CH4) reacts with excess oxygen gas (O2) to produce carbon dioxide (CO2) and water (H2O). What is the percent yield of carbon dioxide if the actual yield is 29.8 grams and the theoretical yield is 0.814 moles?
65.6%
71.6%
83.2%
91.4%

Answer 1

(29.8 g) / [0.184 mol (44.00964 g CO2/mol)] =0.832= 83.2% yield CO2

(hope this helps)

Answer 2

Answer:

83.2%

Explanation:

Percent yield is the ratio of actual yield to the theoretical yield.  

Percent yield = actual yield/ theoretical yield x 100

Moles of CO₂ = 0.184 mol

Molar mass of CO₂ = 44 g/mol

Mass of CO₂ = 0.814 mol x 44 g/mol =  35.816 g

Actual yield = 29.8 g

Theoretical yield =    35.816 g

Percent yield = 29.8 g/   35.816 g x 100 = 83.2%