Question

A right cylindrical container perfectly holds 5 tennis balls placed one above the other. The radius of each ball is 3.35 centimeters. What is the approximate volume of the unoccupied space in the container?

Answer 1

Answer: 394 cm3

Step-by-step explanation:

volume of cylinder - volume of 5 balls=extra volume

voc=πr2h=1181.09

pi=22/7

r=3.35

h= 5 x diameter of ball=33.5 (diameter = 2r)

vo5b=5(4/3πr3)=787.4

r=3.35

ev=voc-vo5b

=393.69

ROUND TO 394