Respuesta :
If you are looking for a line: remember point-slope form.
In this question you have a point (5,0) and you can get the slope from the equation. Since parallel lines have the same slope you can just use 4/5.
Just plug the numbers into the equation: y-y1=m(x-x1)
y-0=4/5(x-5)
Therefore y=4/5x-4
In this question you have a point (5,0) and you can get the slope from the equation. Since parallel lines have the same slope you can just use 4/5.
Just plug the numbers into the equation: y-y1=m(x-x1)
y-0=4/5(x-5)
Therefore y=4/5x-4
To be parallel lines both must have the same slope. Our reference line is:
y=0.8x-3 so the slope is 0.8, given the point (5,0) we can solve for the y-intercept, or "b" of y=mx+b for our parallel line.
0=0.8(5)+b
0=4+b
b=-4 so
y=0.8x-4 is the parallel line to y=0.8x-3 that passes through (5,0)
y=0.8x-3 so the slope is 0.8, given the point (5,0) we can solve for the y-intercept, or "b" of y=mx+b for our parallel line.
0=0.8(5)+b
0=4+b
b=-4 so
y=0.8x-4 is the parallel line to y=0.8x-3 that passes through (5,0)