After the first term in a sequence, the ratio of each term to the preceding term is r. If the first term is a, what is the third term?


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first term is a₁.  Second term I call a₂.  We know that a₂/a₁ = r.  The third term is a₃ and we know also that a₃/a₂ = r.  Set these r's equal
a₃/a₂ = a₂/a₁.  solve for a₃ : a₃ = (a₂)²/a₁.  Or a₃ = a₂r

The third term is,[tex]a_3=a_2r[/tex]

Suppose that the first term is a₁.

and the Second term call a₂.  

What is the common difference?

Suppose that the first term is [tex]a_1[/tex] and second term is  [tex]a_2[/tex]  then the conman difference can be calculated by,

[tex]a_2/a_1 = r.[/tex]

The third term is a₃ and we know also that [tex]a_3/a_2 = r.[/tex]

Set these r's equal

[tex]a_3/a_2 = a_2/a_1[/tex]

solve for a₃ : a₃ = (a₂)²/a₁

[tex]a_3=\frac{(a_2)^{2} }{a_1} \\a_3=a_2r......since (\frac{a_2}{a_1})=r[/tex]

Therefore we get,the third term is,[tex]a_3=a_2r[/tex]

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