Respuesta :
as i am reading the problem, i notice they give two concentrations (M), a volume and asking for the other volume; this should be a hint that we need to use the dilution formula---> M1V1 = M2V2
M1= 2.55 M
V1= ?
M2= 0.75 M
V2= 125 mL
now, we plug in the values into the formula
(2.55 x V1) = (0.75 x 125)
V1= 36.8 mL
M1= 2.55 M
V1= ?
M2= 0.75 M
V2= 125 mL
now, we plug in the values into the formula
(2.55 x V1) = (0.75 x 125)
V1= 36.8 mL
Answer:
36.7 milliliters of 2.55M NaOH will be needed
Explanation:
Molarity of NaOH solution = [tex]M_1=2.55 M[/tex]
[tex]V_1=? [/tex]
Molarity of 125 mL NaOH solution = [tex]M_2=0.75 M[/tex]
[tex]V_2=125 mL = 0.125 L[/tex]
Using dilution formula :
[tex]M_1V_1=M_2V_2[/tex]
[tex]2.55 M \times V_1=0.75 M\times 0.125 L[/tex]
[tex]V_1=0.0367 L = 36.7 mL[/tex]
36.7 milliliters of 2.55M NaOH will be needed
