Question

find the 32nd term of the sequence 34, 37, 40, 43

Answer 1

increases by 3 each time
aritmetic sequence, firsrt term is 34, 3=common differnce
an=a1+d(n-1) is da formlua
a1=first term
d=common differnce
an=34+3(n-1)
so 32n'd term is
a32=34+3(32-1)
a32=34+3(31)
a32=34+93
a32=127
the 32nd term is 127

Answer 2

32nd term of the sequence is 127.

Given that;

Sequence 34, 37, 40, 43

Find:

32nd term of the sequence

Computation:

First term a = 34

Common difference d = a2 - a1 = 37 - 34 = 3

Number of term n = 32

So,

An = a + (n - 1)d

A32 = 34 + (32 - 1)3

A32 = 34 + (31)3

A32 = 34 + 93

A32 = 127

32nd term of the sequence = 127

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