Respuesta :
hmmm same as the other you posted... is the graph of y= cos(θ), but with a negative Amplitude of -1, and a B component of 3
let's check the period again [tex]\bf \cfrac{2\pi }{B}\iff \cfrac{2\pi }{3}[/tex]
so, is the same graph, with a period of [tex]\bf \cfrac{2\pi }{3}[/tex] and the negative amplitude will simply, retain the same midline, but the graph will be turned upside-down
let's check the period again [tex]\bf \cfrac{2\pi }{B}\iff \cfrac{2\pi }{3}[/tex]
so, is the same graph, with a period of [tex]\bf \cfrac{2\pi }{3}[/tex] and the negative amplitude will simply, retain the same midline, but the graph will be turned upside-down
Answer:
Refer the attached graph
Step-by-step explanation:
Given : Function [tex]y=-cos3\theta[/tex]
To Sketch the given function :
General form: [tex]y=\alpha cos(\beta\theta)[/tex]
where [tex]\alpha[/tex]=amplitude and [tex]\frac{2\pi}{\beta}[/tex] = period
According to question, [tex]y=-cos3\theta[/tex]
[tex]\alpha[/tex]=-1 and [tex]\frac{2\pi}{3}[/tex] = period
From [tex](0,\frac{2\pi }{3} )[/tex] cosine function sketch refer the attached graph .
