Respuesta :

hmmm same as the other you posted... is the graph of y= cos(θ), but with a negative Amplitude of -1, and a B component of 3

let's check the period again  [tex]\bf \cfrac{2\pi }{B}\iff \cfrac{2\pi }{3}[/tex]

so, is the same graph, with a period of  [tex]\bf \cfrac{2\pi }{3}[/tex] and the negative amplitude will simply, retain the same midline, but the graph will be turned upside-down

Answer:

 Refer the attached graph            

Step-by-step explanation:

Given : Function [tex]y=-cos3\theta[/tex]

To Sketch the given function :

General form:   [tex]y=\alpha cos(\beta\theta)[/tex]

where [tex]\alpha[/tex]=amplitude and [tex]\frac{2\pi}{\beta}[/tex] = period

According to question,  [tex]y=-cos3\theta[/tex]

[tex]\alpha[/tex]=-1 and  [tex]\frac{2\pi}{3}[/tex] = period

From [tex](0,\frac{2\pi }{3} )[/tex] cosine function sketch refer the attached graph .


Ver imagen DodieZollner
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