if the average of 15 numbers is 7, the sum should be [tex]15*7=105[/tex]
if for 6 of the numbers, he sees 9 instead of 7, he is counting 2 additional units per number, so his sum will be greater by [tex]2*6=12[/tex], therefore the sum he gets is [tex]105+12=117[/tex]
from that, the average he calculates is [tex] \frac{117}{15} = 7.8 [/tex]