Respuesta :
We have:
p=0.02
n=5
k=2
[tex]P(success ~2)=_nC_k~*~(p)^k~*~(1-p)^{n-k}\\~\\~\\P(success ~2)=5C2~*~0.02^2*0.98^3=0.003765[/tex]
SO that the probability that the sample contains exactly two defective parts would be 0.38%
p=0.02
n=5
k=2
[tex]P(success ~2)=_nC_k~*~(p)^k~*~(1-p)^{n-k}\\~\\~\\P(success ~2)=5C2~*~0.02^2*0.98^3=0.003765[/tex]
SO that the probability that the sample contains exactly two defective parts would be 0.38%