What is the slope of a line that passes through (–12,15) and (0,4)?       

A.-12/11   B. 11/12   C. -11/12   D. 12/11

Respuesta :

C is the answer -11/12
Answer:  The slope is:  [tex] -\frac{11}{12} [/tex] .
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Explanation:
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Given two points on the line:  (x₁, y₁) ;  and:  (x₂, y₂) ;

which are given:  (-12, 15) and (0, 4) ;  in which: 
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                              x₁  = -12 ,  y₁  = 15 ,  x₂ = 0,  y₂ = 4 ;
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The slope, "m", is calculated as follows:
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   m = (y₂ − y₁) / (x₂ − x₁)  =  (4 − 15) / [0 − (-12)] ;
                                         =  (4 − 15) / (0 + 12) ;
                                         =    -11 / 12 .
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                            The slope, "m" is:   - 11/12 .
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