Question

3H2(g) + N2(g)= 2NH3(g)
How many moles of NH3 can be produced from 24.0 mol of H2 and excess N2

Answer 1

The ratio of H2 moles to NH3 moles is 3:2 which you can see from the numbers in the equation. This means if you can have 24 moles of H2 you can use this ratio and you can produce 16 moles of NH3

Answer 2

Answer : The number of moles of $NH_3$ produced can be 16 moles.

Solution : Given,

Moles of $H_2$ = 24.0 mol

The balanced chemical reaction is,

$3H_2(g)+N_2(g)\rightarrow 2NH_3(g)$

By the stoichiometry, we can say that 3 moles of hydrogen gas react with 1 mole of nitrogen gas to give 2 moles of ammonia gas as a product.

From the balanced reaction we conclude that

As, 3 moles of $H_2$ react to give 2 mole of $NH_3$

So, 24.0 moles of $H_2$ react to give $\frac{24.0}{3}\times 2=16$ moles of $NH_3$

Therefore, the number of moles of $NH_3$ produced can be 16 moles.