A 1.5 L container holds 0.50 grams of an unknown gas at a pressure of 0.44 atm and a temperature of 50. C. What is the molar mass of the unknown gas?
A.) 0.16g/mol
B.) 0.025 g/mol
C.) 2030 g/mol
D.) 20.1 g/mol
To simplify the problem, we assume that the gas is ideal so we use the ideal gas equation for this which is expressed as PV=nRT. First, we calculate for the number of moles, n, of the system.
n = PV/RT n = 0.44(1.5) / 0.08205(323.15) n = 0.025 mol
Molar mass = 0.50 g / 0.025 mol Molar mass = 20 g / mol
